Question

A container has a large cylindrical lower part with a long thin cylindrical neck open at the top. The lower part of the container holds 20.0 m3 of water and the surface area of the bottom of the container is 8.00 m2. The height of the lower part of the container is 2.50 m, and the neck contains a column of water 8.50 m high. The total volume of the column of water in the neck is 0.200 m3. What is the magnitude of the force exerted by the water on the bottom of the container?

Answer 1

8.6*10^5N

Step-by-step explanation:

Pressure of the water = density of water * height of the water * acceleration due to gravity

Pressure of water = 1000*9.81*(2.5 + 8.50)

Pressure of the water = 107910 = 1.08*10^5

And Pressure = force / A

Force = Pressure * A(surface area of the container)

Force = 1.08*10^5 * 8 = 863280 = 8.6*10^5N