Question

A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a constant force (in contrast to the constant power in Part A). If such a sports car went from zero to 29.0 mph in time 1.50 s , how long would it take to go from zero to 58.0 mph

Answer 1

It would take 3.00 s

Explanation:

For a constant force system, the acceleration (a) of the system is constant.

In the first instance,

Initial velocity = 0 mph

final velocity = 29.0 mph

time taken = 1.50 s

`acceleration = (final velociity(v) - initial velocity (u))/(time taken)`

`acceleration = (29.0 - 0)/(1.50)`

`acceleration = 19.33 mph^(2)`

Since the system is a constant force system,

Initial velocity = 0 mph

final velocity = 58.0 mph

time taken = ?

`acceleration = (final velociity(v) - initial velocity (u))/(time taken)`

`19.33 = (58.0 - 0)/(t)`

t = \frac{58.0}{19.33} = 3.00 s