Question

At stp if 1.00 mole of gas occupies 22.4 l then 0.200 mole of gas would occupy ________ l under the same conditions.

Answer 1

V = 4.48 l

Step-by-step explanation:

Standard temperature and pressure is at the temperature at 273 K (0 C) and pressure of 1 atm (101325 N/m2 or 760 mmHg).

The general gas law,

`PV = nRT`

Considering the first condition

n = 1.00 mole,
`P = P_(1)`,
`T = T_(1)`, R = Constant, V = 22.4 l

`P_(1)V_(1) = nRT_(1)` ---------------------Eqn 1

n = 0.200 mole,
`P = P_(2)`,
`T = T_(2)`, R = Constant, V = ??

`P_(2)V_(2) = nRT_(2)` ---------------------Eqn 2

Under the same condition,

`P_(1)` =
`P_(2)`,
`T_(1)` =
`T_(2)`

Dividing Eqn 1 by Eqn 2

`(P_(1)V_(1))/(P_(2)V_(2)) = (n_(1) RT_(1))/(n_(2) RT_(2))`

`(V_(1))/(V_(2)) = (n_(1))/(n_(2))`

`V_(2) = (n_(2) V_(1) )/(n_(1))`

V =
`(0.200 * 22.4)/(1.00)`

V = 4.48 l