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A helicopter hovers 40 ft above the ground. ＀en the helicopter climbs See Problem 2.at a rate of 21 ft/s. Write a rule that represents the helicopter’s height h above the ground as a function of time t. What is the helicopter’s height after 45 s?

1 Answer

7 votes

Answer:

h = rt

945ft

Explanation:

Let h be height, r be rate and t be time.

The rule can be written as h = rt

The height after the 40 seconds can be calculated using the formula. We substitute 21ft/s for r and 46s for t.

The height is thus h = 21 × 45 = 945ft

User LHristov
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