Question

For a turning operation, you have selected a high-speed steel (HSS) tool and turning a hot rolled free machining steel. Your depth of cut will be 0.105 in. The diameter of the workpiece is 1.00 in. a. Using a speed of 105 sfpm and a feed of 0.015, calculate the metal removal rate (MRR).

Answer 1

MRR = 1.984

Step-by-step explanation:

Given that

Depth of cut ,d=0.105 in

Diameter D= 1 in

Speed V= 105 sfpm

feed f= 0.015 ipr

Now the metal removal rate given as

MRR= 12 f V d

d= depth of cut

V= Speed

f=Feed

MRR= Metal removal rate

By putting the values

MRR= 12 f V d

MRR = 12 x 0.015 x 105 x 0.105

MRR = 1.984

Therefore answer is -

1.944