Question

C2d3 has a solubility product constant of 9.14×10−9. What is the molar solubility of c2d3?

Answer 1

Answer : The molar solubility of
`C_2d_3` is
`9.67* 10^(-3)M`

Explanation :

The solubility equilibrium reaction will be:

`C_2d_3\rightleftharpoons 2C^(3+)+3d^(2-)`

The expression for solubility constant for this reaction will be,

Let the molar solubility be, 'x'

`K_(sp)=(2x)^2* (3x)^3`

Now put all the given values in this expression, we get:

`9.14* 10^(-9)=108x^5`

`x=9.67* 10^(-3)M`

Therefore, the molar solubility of
`C_2d_3` is
`9.67* 10^(-3)M`