Solve the system of equations by substituting 15x+31y=−3 x=−y+3

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Pixelistik · Answer 1 · 2020-03-12T22:42:40+0000

Answer:

x=6

y=-3

Explanation:

Substitute (-y + 3) for x in the first equation:

15(-y+3)+31y=-3

Expand:

45-15y+31y=-3

Simplify:

45+16y=-3

Subtact 45 from both sides:

16y=-48

Divide both sides by 16:

y=-3

Substitute -3 for y in either equation:

x=-(-3)+3

x=6

Solve the system of equations by substituting 15x+31y=−3 x=−y+3

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Solve the system of equations by substituting 15x+31y=−3 x=−y+3