Question

Solve the system of equations by substituting

15x+31y=−3
x=−y+3
​

Answer 1

`x=6`

`y=-3`

Explanation:

Substitute (-y + 3) for x in the first equation:

`15(-y+3)+31y=-3`

Expand:

`45-15y+31y=-3`

Simplify:

`45+16y=-3`

Subtact 45 from both sides:

`16y=-48`

Divide both sides by 16:

`y=-3`

Substitute -3 for y in either equation:

`x=-(-3)+3`

`x=6`

Answer 2

x=6 y=-3

Explanation: