Question

What pressure would be required to take 100.0ml of a gas at 103.0kPa and squish it down to 2.00ml, assuming temperature and number of moles is held constant?

Answer 1

The pressure required = 5150 kPa

Further explanation

Given

V₁ = 100 ml

P₁ = 103 kPa

V₂= 2 ml

Required

Pressure

Solution

Boyle's Law

At a constant temperature, the gas volume is inversely proportional to the pressure applied

`\rm p_1V_1=p_2.V_2\\\\(p_1)/(p_2)=(V_2)/(V_1)`

`\tt P_2=(P_1.V_1)/(V_2)\\\\P_2=(103* 100)/(2)\\\\P_2=5150~kPa`