Answer:
In order to obtain 30 gallons of mixture with 35% of antifreeze we will mix 25 gallons of brand-1 product and 5 gallons of brand-2 product.
Step-by-step explanation:
Let volume of antifreeze required of brand -1 be x
Let volume of antifreeze required of brand -2 be y.
Total volume of antifreeze mixture required = 30 gallons
x + y = 30 gal ...[1]
Percentage of antifreeze in brand-1 product = 30%
Percentage of antifreeze in brand-1 product = 60%
Desired percentage of antifreeze required in 30 gallons of solution = 35%
30% of x + 60% of y = 35% of 30 gallons
...[2]
On solving [1] and [2] we get:
x = 25 gallons
y = 5 gallons
In order to obtain 30 gallons of mixture with 35% of antifreeze we will mix 25 gallons of brand-1 product and 5 gallons of brand-2 product.