Answer:
![(3)/(16) \textrm{of the gargantuas will be unplanted}.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4j5rqq76hs22kbfiups94vqcwtqk20enwn.png)
Explanation:
Given: Browns have planted 3/16 tomatoes, 1/4 cabbage and 3/8 peppers.
First lets find out the total fraction of planted.
![(3)/(16) +(1)/(4) +(3)/(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mvk0u278jaq83q41nfxkri7xvbviizrzap.png)
Now taking LCD for 16,4 and 8 to add up the fraction.
∴ LCD is 16
Next adding the fraction,
![(3* 1+1* 4+ 3* 2)/(16) = (13)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mrglqic3e02zv423z5c72tlp0fl4baaxb8.png)
∴ Total fraction of planted gargantuas is
![(13)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fu6yq8qnai8tnal1e8onls63pnblxfch67.png)
Lets take the size of gragantuas as ``1``
∴ To find the un planted fraction of gargantuas.
![(1- \textrm{Total fraction of planted part of gargantuas})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9cte644cgjwq7imfcwfz3lt718n10kyvq0.png)
=
![1-(13)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aqp3vtxsp90wyz9a7qnl0f92nzo3906wn2.png)
=
∴ 3/16 is the unplanted fraction of gargantuas.