Answer:
a) 16.97o b) 0.305
Step-by-step explanation:
Using bank angle formula
Tan ( bank angle) = V^2/(r*g)
Where V = speed of the traffic = 75Km/hr, converting it to m/s = 75 *1000m/(3600s) = 20.833m/s, r = radius of the curved path in metres and g = acceleration due to gravity in m/s^2
Tan (bank angle) = 20.833 ^2/( 145 *9.81) = 0.305
Bank angle = tan inverse of (0.305) = 16.97o
b) Using the formula when the road is unbanked
Vmax = √coefficient friction *r *9.81
V^2 max/(r*g) = coefficient of friction
Coefficient of friction = 0.305