Answer:
The work done by the force is 6μJ
Step-by-step explanation:
Suppose, A 30 nC charge is moved from a point where V₁ = 130 V to a point where V₂ = -70 V.
We need to calculate the work done by the force
Using formula of work done
![W=-q\Delta V](https://img.qammunity.org/2020/formulas/physics/high-school/230to42p1p6oyacg1bvlianz90lzwlpu9r.png)
Where, q = charge
=potential difference
Put the value into the formula
![W=-30*10^(-9)*(-70-130)](https://img.qammunity.org/2020/formulas/physics/high-school/x3wv8at1h9bew01g4mggkw430t4xt67nox.png)
![W=0.000006\ J](https://img.qammunity.org/2020/formulas/physics/high-school/uu9dnqnzdrhdu07wsjl5krkg37b7uvfvgc.png)
![W=6*10^(-6)\ J](https://img.qammunity.org/2020/formulas/physics/high-school/o9kvid3195gvvjf8usu9te5j29j36dlnyw.png)
![W=6\ \mu J](https://img.qammunity.org/2020/formulas/physics/high-school/zd91t5t0abfn7pyy6r0mgvhtbcxomictnj.png)
Hence, The work done by the force is 6μJ.