Answer:
Center of mass lies 24 m in front of center of mass of second wagon.
Step-by-step explanation:
Suppose A 1200 kg station wagon is moving along a straight highway at 12.0 m/s. Another car with mass 1800 kg and speed 20.0 m/s.
Given that,
Mass of first wagon = 1200 kg
Mass of second wagon = 180 kg
Distance = 40 m
We need to calculate the position of the center of mass of the system
Using formula of center mass
![x_(cm)=(m_(1)x_(1)+m_(2)x_(2))/(m_(1)+m_(2))](https://img.qammunity.org/2020/formulas/physics/high-school/97tn08leh9ml2f6rgd9svz4ny87ixycgez.png)
![x_(cm)=(1200*0+1800*40)/(1200+1800)](https://img.qammunity.org/2020/formulas/physics/high-school/p9j8ph6iq1nrs9o24ka70qqrp76f6nwlyf.png)
![x_(cm)=24\ m](https://img.qammunity.org/2020/formulas/physics/high-school/9y41t3zpk5t4pp6mqyjrypg5z9ewlu8fxp.png)
Hence, Center of mass lies 24 m in front of center of mass of second wagon.