Answer:
164.82 g
Step-by-step explanation:
Given data:
Mass of AgNO₃ = 195 g
Mass of AgCl = ?
Solution:
Chemical equation:
NaCl + AgNO₃ → AgCl + NaNO₃
Number of moles of AgNO₃:
Number of moles = mass/molar mass
Number of moles = 195 g / 169.87 g/mol
Number of moles =1.15 mol
Now we will compare the moles of AgNO₃ with AgCl.
AgNO₃ : AgCl
1 : 1
1.15 : 1.15
Mass of AgCl:
Mass = number of moles × molar mass
Mass = 1.15 mol × 143.32 g/mol
Mass = 164.82 g