Answer:
No, They will do it in more than an hour
t=1,1 h
Explanation:
Vh=1mile/12min, Vt=1mile/15min They will meet to same time th=tt
sh=x, st=10-x, so V=s/t we have Vh=sh/t ; Vt=st/t ; t=(sh/Vh) = (st/Vt);
; so
: if Vh=sh/t then

Note: V=s/t : but in this case are 12 min (t) per mile (s), so