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Do han and tyler meet on the path within 1 hour?Explain or show your reasoning At 10:00 a.M., Han and Tyler both started running toward each other from opposite ends of a 10-mile path along a river. Han runs at a pace of 12 minutes per mile. Tyler run at a pace o 15 minutes per mile.

User Mielk
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Answer:

No, They will do it in more than an hour

t=1,1 h

Explanation:

Vh=1mile/12min, Vt=1mile/15min They will meet to same time th=tt

sh=x, st=10-x, so V=s/t we have Vh=sh/t ; Vt=st/t ; t=(sh/Vh) = (st/Vt);


(x)/((1)/(12) ) = (10-x)/((1)/(15) )\\(x)/(15)=(10-x)/(12)\\  12x=15(10-x); so
12x+15x=150; 27x=150; x=(150)/(27)=(150)/(9) mile: if Vh=sh/t then
t=((50)/(9)mile )/((1mile)/(12min) ) =(600)/(9)min*(h)/(60min)=1,1 h

Note: V=s/t : but in this case are 12 min (t) per mile (s), so
V=(mile)/(12min)

Do han and tyler meet on the path within 1 hour?Explain or show your reasoning At-example-1
User Don Zacharias
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