Answer:
a) m₂ = 4 kg , b) I_disk / I sphere = 5/4
Step-by-step explanation:
a) This exercise is requested to make several comparisons on the moments of inertia and different objects, the moment of inertia with respect to the center of mass of a spherical shell is
I = 2/3 m R²
Let's calculate the moment of inertia of the sphere diameter (d = 2m8 and mass (m₁ = 1 kg)
r₁ = d / 2
r₁ = 2/2
r₁ = 1 m
I₁ = 2/3 m₁ r₁²
The other shell as a diameter (d = 1m)
r₂ = d / 2
r₂ = 1 / 2
r₂ = 0.5 m
I₂ = 2/3 m₂ r₂²
As they indicate that the two moments of inertia are equal
I₁ = I₂
m₁ r₁² = m₂ r₂²
m₂ = m₁ (r₁ / r₂)²
m₂ = 1 (1 / 0.5)²
m₂ = 4 kg
b) it is requested to find the relation of the moment of inertia of a disk and a sphere.
Moment of inertia disk I_disk = ½ m r²
Moment of inertia sphere I_ sphere = 2/5 m r²
The relationship between you is the division of moments of inertia
I_disk I _sphere = (1/2 m r²) / (2/5 m r²)
I_disk / I sphere = 5/4