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Which of the following represents 3x-5y+10=0 written in slope-intercept form?

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For this case we have that by definition, the equation of a line in the slope-intercept form is given by:


y = mx + b

Where:

m: Is the slope

b: Is the cut-off point with the y axis

We have the following equation:


3x-5y + 10 = 0

We manipulate algebraically:

We subtract 10 from both sides of the equation:


3x-5y = -10

We subtract 3x from both sides of the equation:


-5y = -3x-10

We multiply by -1 on both sides of the equation:


5y = 3x + 10

We divide between 5 on both sides of the equation:


y = \frac {3} {5} x + \frac {10} {5}\\y = \frac {3} {5} x + 2

Thus, the equation in the slope-intercept form is
y = \frac {3} {5} x + 2

Answer:


y = \frac {3} {5} x + 2

User Karl Pokus
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