Answer:
131.39863 m/s
683205.94 Joules
Step-by-step explanation:
m = Mass of person = 80 kg
g = Acceleration due to gravity = 9.81 m/s²
h = Height of the drop = 880 m
v = Speed
= Maximum speed = 140 km/h
Here the Potential and Kinetic energies are conserved

The velocity of Fritz Strobl is 131.39863 m/s
Taking friction into consideration

The work done by friction is 683205.94 Joules