Question

Evaluate the expression
3/2y-3+5/3z
y=6 z=3

Answer 1

= 11

Explanation:

Given that:

= 3/2y-3+5/3z

where:

y=6 , z=3

By putting values we get:

=3/2(6)-3+5/3(3)

After cancellation we get:

= 3 * (3) - 3 + 5

= 9 -3 + 5

= 11

I hope it will help you!