Question

An average platelet is a cylinder 2 um in diameter and 0.2 m in height. Platelets have approximately 75,000 integrin molecules on their membrane surface. If each integrin molecule is represented as a cylinder that is 10 nm in diameter, what percentage of the platelet surface area is covered by integrins?

Answer 1

93.75 %

Step-by-step explanation:

Base surface area of a cylinder is given by

`2(pi)r^2`

where r is the radius and h is the height

The surface area of platelet is

`[tex]2(pi)r^2`\\ 2 * 3.14* (\frac{2*10^{-6}}{2})^2\\ 6.28*10^{-12}\\6.28 *10^{-12}[/tex]

Surface area of a integrin molecule

`3.14 * (5 *10^(-9))^2\\75000 * 7.85 * 10^-17\\= 5.8875 *10^(-12)`

Percentage share of surface area

`(5.8875 * 10^(-12))/(6.28* 10^(-12)) * 100\\93.75`

93.75 %