Question

NEED THIS NOW PLZZ!!!!

Write an equation for the line graphed.

A: y=2/3x-3
B: y=2/3x+3
C: y=3/2x-3
D: y=3/2x+3
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Answer 1

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

`y = mx + b`

Where:

m: Is the slope

b: Is the cut-off point with the y axis

According to the image we have that the line goes through the following points:

`(x_ {1}, y_ {1}) :( 0, -3)\\(x_ {2}, y_ {2}) :( 6,1)`

Then, the slope is of the form:

`m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {1 - (- 3)} {6-0} = \frac {1 + 3} {6} = \frac {4} {6} = \frac {2} {3}`

Thus, the equation is of the form:

`y = \frac {2} {3} x + b`

We know that the cut-off point is
`b = -3,` finally the equation is:

`y = \frac {2} {3} x-3`

Answer:

`y = \frac {2} {3} x-3`