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Calculate the recoil velocity in the horizontal direction, in meters per second, of a 1.25-kg plunger that directly interacts with a 0.0175-kg bullet fired at 585 m/s from the gun. Take the firing direction to be the positive direction.

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Answer:


v_1=-8.19\ m/s'

Step-by-step explanation:

It is given that,

Mass of the plunger,
m_1=1.25\ kg

Mass of the bullet,
m_2=0.0175\ kg

Initially both plunger and the bullet are at rest,
u_1=u_2=0

Final speed of the bullet,
v_2=585\ m/s

Let
v_1 is the final speed of the plunger. Using the conservation of momentum to find it. The equation is as follows :


m_1u_1+m_2u_2=m_1v_1+m_2v_2

Since,
u_1=u_2=0


m_1v_1+m_2v_2=0


v_1=-(m_2v_2)/(m_1)


v_1=-(0.0175* 585)/(1.25)


v_1=-8.19\ m/s

So, the recoil velocity of the plunger is 8.19 m/s. Hence, this is the required solution.

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