Question

Calculate the force between two objects that have

masses of 140 kg and 160 kg and are separated by a
distance of 0.895 m.​

Answer 1

`\text { The force between the given two objects is } 1.865 * 10^(-6) \mathrm{N}`

Step-by-step explanation:

As per given question,

`m_(1) \text { is } 140 \mathrm{kg}`

`m_(2) \text { is } 160 \mathrm{kg}`

R is 0.895 m

The force between two objects is

`\mathrm{F}=(G m_(1) m_(2))/(R^(2))`

Where,

F is the force of attraction between two objects in Newton’s (N)

`\text { G is the Universal Gravitational Constant }=6.674 * 10^(-11) \mathrm{N}-\mathrm{m}^(2) / \mathrm{kg}^(2)`

`m_(1) \text { and } m_(2) \text { are the masses of the two objects in kilograms (kg) }`

R is the separation in meters (m) between the objects

Substitute the given values in the above formula,

`F=(6.674 * 10^(-11) * 140 * 160)/(0.895^(2))`

`F=(1.494 * 10^(-6))/(0.801)`

`\mathrm{F}=1.865 * 10^(-6)`

`\text { The force between the given two objects is } 1.865 * 10^(-6) \mathrm{N}`