They need to admit 43 more cars to make at least $500
Solution:
Given, A drive in theater charges $3.50 per car,
The drive in already admitted 100 cars,
Then, money collected until now is $ 3.50 x 100 = $ 350
We have to solve an inequality to find the number of cars the drive in needs to admit to make atleast 500$
Now, let the number of cars need to be admitted be "n"
Then, inequality is:
collected amount + needed amount ≥ $ 500
$ 350 + $ 3.50 x n ≥ $ 500
350 + 3.5n ≥ 500
3.5n ≥ 500 – 350
On solving, we get
3.5n ≥ 150
n ≥ 42.857
As number of cars can’t be fractions, n = 43
Hence, they need to admit 43 more cars to make at least $500