Question

How do you solve
f(x)=-2(x+3)^2 =5

Answer 1

x=(-6+/-sqrt(10)*i)/2

Explanation:

-2(x+3)^2=5

-2(x+3)(x+3)=5

-2(x^2+3x+3x+9)=5

-2(x^2+6x+9)=5

-2x^2-12x-18=5

-2x^2-12x-18-5=0

-2x^2-12x-23=0

2x^2+12x+23=0

Apply the quadratic formula,

you get x=(-6+/-sqrt(10)*i)/2.