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How much work is required to lift a 0.500 kg block 18.5 m?

1 Answer

3 votes

Answer:

Work = 90.65 j

Step-by-step explanation:

Given data:

Mass = 0.500 Kg

Distance = 18.5 m

Work done = ?

Solution:

Work = force . distance

Force = mg

Work = mg.distance

Work = mgh

Work = 0.500 Kg × 9.8 m/s²× 18.5 m

Work = 90.65 Kg .m²/s²

Kg .m²/s² = j

Work = 90.65 j

User Affan Ahmad
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