Mass of water required = 64.42 g
Further explanation
Given
Reaction
6CO2 + 6H2O → C6H12O6 + 6O2
157.35 g CO2
Required
mass of water
Solution
mol CO₂ = mass : MW CO₂
mol CO₂ = 157.35 g : 44.01 g/mol
mol CO₂ = 3.575
From the equation, mol ratio CO₂ : H₂O = 6 : 6, so mol H₂O = mol CO₂=3.575
Mass H₂O = mol x MW H₂O
mass H₂O = 3.575 x 18.02
mass H₂O = 64.42 g