Question

The farmer had 28 cows. He wanted to bring them into the milking shed in groups of 7. How many groups of cows did the farmer bring into the milking shed?

The farmer knew he could solve this problem using the number sentence 28÷7=□ .

Which is another way the farmer could solve this problem?

Add 28 and 7.

Add 7 to 28. Keep adding 7 to the answer for a total of seven times.

Subtract 7 from 28. Keep subtracting 7 from the answer until he gets to 0. Then count the number of times 7 was subtracted.

Multiply 28 by 7.

Answer 1

(C) Subtract 7 from 28. Keep subtracting 7 from answer until he gets to 0. Then count the number of times 7 was subtracted.

This method is another suitable solution to problem

Explanation:

Total number of cows the farmer has = 28 cows

Number of cows in 1 shed = 7

The number of sheds used to keep 28 cows is 28 ÷ 7 = 4 sheds

⇒4 sheds are needed to keep 28 cows.

Now choosing an alternate method:

1) Add 28 and 7 = 28 + 7 = 35 sheds

But 35 sheds ≠ 4 sheds

Hence, NOT AN APPROPRIATE METHOD.

2)Add 7 to 28. Keep adding 7 to the answer for a total of seven times.

28 + 7 .... 7 times = 28 + 7 + 7 + 7 + 7 /+ 7 + 7 + 7 = 77 ≠ 4 sheds

NOT AN APPROPRIATE METHOD.

3)Subtract 7 from 28. Keep subtracting 7 from answer until he gets to 0.

28 - 7 = 21

21 - 7 = 14

14 -7 = 7 and 7 - 7 - 0

Hence, in 4 times the answer is 0

So, the number of sheds required is 4

AN APPROPRIATE METHOD.

4) Multiply 28 by 7.

28 x 7 = 196, 196 ≠ 4 sheds

NOT A APPROPRIATE METHOD.

Hence, the ONLY alternate method to count the totals sheds required is

Subtract 7 from 28. Keep subtracting 7 from the answer until he gets to 0.