Question

27. (a) What magnification is produced by a 0.150 cm focal length microscope objective that is 0.155 cm from the object being viewed? (b) What is the overall magnification if an 8× eyepiece (one that produces a magnification of 8.00) is used?

Answer 1

magnification = - 30

overall magnification = -240

Step-by-step explanation:

given data

Focal length of microscope objective f = 0.150 cm

Object distance from microscope objective do = 0.155 cm

magnification by eyepiece = 8 ×

to find out

What magnification is produced and overall magnification

solution

we consider here Image distance from microscope objective is = di

so that

Magnification produced by objective will be = -
`(di)/(do)`

so we find here di by given equation that is

`(1)/(do) +(1)/(di) = (1)/(f)` ..................1

`(1)/(di) = (1)/(0.150) - (1)/(0.155)`

di = 4.65 cm

so that magnification by object will be

magnification = -
`(di)/(do)`

magnification = -
`(4.65)/(0.155)`

magnification = - 30

and

overall magnification will be

overall magnification = magnification by objective × magnification by eyepiece ........................2

overall magnification = -30 × 8

overall magnification = -240