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jenny solves x^2 + 2x- 3 = 0 and finds the solutions are x = -3 and 1 she then graphs the function and gets the graph shown how are the solutions related to the y-intercept?

jenny solves x^2 + 2x- 3 = 0 and finds the solutions are x = -3 and 1 she then graphs-example-1

2 Answers

5 votes

Answer:

On usatestperp its A: They are the same values.

Explanation:

The x-intercepts are were the graph crosses the x-axis. From the graph you can see that it crosses at x = -3 and 1, which are the solutions. Therefore, they are the same values.

User Inikulin
by
7.9k points
3 votes

Answer:

See explanation

Explanation:

Jenny solves
x^2 + 2x-3 = 0 and finds the solutions are
x = -3 and
x=1.

So, she can write this equation as


(x-(-3))(x-1)=0\\ \\(x+3)(x-1)=0

The y-intercept is at
x=0. Substitute it into the previous equation:


(0+3)(0-1)=3\cdot (-1)=-3

From the graph, she can see that y-intercept is at point (0,-3), so y-intercept -3 is the product of solutions to the quadratic equation.

User Fayza Nawaz
by
8.0k points

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