Question

The force required to stretch a Hooke’s-law spring varies from 0 N to 43.2 N as we stretch the spring by moving one end 14.4 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m.

Answer 1

Spring constant = 300 N/m

Step-by-step explanation:

For a spring we have force is the product of spring constant and displacement.

Force = Spring constant x Displacement

F = k x

Here Force , F = 43.2 - 0 = 43.2 N

Displacement, x = 14.4 cm = 0.144 m

Substituting

F = k x

43.2 = k x 0.144

k= 300 N/m

Spring constant = 300 N/m