Answer:
The current is 0.08 ampere.
Explanation:
Given:
The current is 1/2 ampere when the resistance is 400 ohms.
Now, the current I in an electrical conductor varies inversely as the resistance R of the conductor.
So, as per formula
![I = (k)/(R)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u8tf1pfxx82jhwrt4nkvvrh5edzdyf5nx6.png)
Solving for "k" using the current 1/2 amperes when the resistance is 400 ohms.
![(1)/(2) = (k)/(400)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oorqprlekls9z2j5b9fc5arsyjwlm730mh.png)
By cross multiplication we get:
![2k=400\\k=(400)/(2)=200](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3pgf0tstb5tnwcmbm8rkvbtnapkyv9qwpc.png)
Putting the value of
for solving the equation:
![I =\frac {200}{R}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z08psbr93z25xbi13jdc5zvrqvunorzi7q.png)
Now, the current when the resistance is 2500 ohms:
![I = (200)/(2500)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jqka46hb9uok6nz8q9t5telfydm9mqoeus.png)
![I = 0.08](https://img.qammunity.org/2020/formulas/mathematics/middle-school/49jf2320czv8dygng6djslhe1su44jeiry.png)
ampere.
Therefore, the current is 0.08 ampere.