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GEOMETRY HELP PLEASE!!! 3 questions

GEOMETRY HELP PLEASE!!! 3 questions-example-1
User Rickp
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1 Answer

1 vote

Answer:

Explanation:

1. Use the Pythagorean theorem


a^2 + b^2 = c^2

In the Pythagorean Theorem equation, a^2 + b^2 = c^2, the two sides called a and b are the legs which are the sides that form the right angle. The side called c is the hypotenuse and is the side opposite the right angle.

In this problem, the legs are x and 6.2 m. Those are called a and b.

The hypotenuse is 12.7 m which is c.


a^2 + b^2 = c^2


x^2 + (6.2~m)^2 = (12.7~m)^2


x^2 + 38.44~m^2 = 161.29~m^2


x^2 = 122.85~m^2


x = √(122.85~m^2)


x = 11.1~m

2.


\tan A = (opp)/(adj)


\tan 15^\circ = (18)/(x)


x\tan 15^\circ = 18


x = (18)/(\tan 15^\circ)


x = 67.2

3. The triangle has a 45-deg angle and a 90-deg angle.

45 + 90 + m<3 = 180

m<3 = 45

The third angle also measures 45 deg. This is a special case called 45-45-90 triangle. The sides opposite the congruent angles are congruent, so x = y. Now we can use the Pythagorean theorem.


a^2 + b^2 = c^2


x^2 + x^2 = (√(10))^2


2x^2 = 10


x^2 = 5


x = √(5)


x = 2.24


y = 2.24

User KubiRoazhon
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