Answer:
Explanation:
1. Use the Pythagorean theorem
![a^2 + b^2 = c^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7f61kw3dl3dz393m0wgdbl1ulni49sr4kp.png)
In the Pythagorean Theorem equation, a^2 + b^2 = c^2, the two sides called a and b are the legs which are the sides that form the right angle. The side called c is the hypotenuse and is the side opposite the right angle.
In this problem, the legs are x and 6.2 m. Those are called a and b.
The hypotenuse is 12.7 m which is c.
![a^2 + b^2 = c^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7f61kw3dl3dz393m0wgdbl1ulni49sr4kp.png)
![x^2 + (6.2~m)^2 = (12.7~m)^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/nrtjbpvilhhwgtl0fvilk50liswuetz2y6.png)
![x^2 + 38.44~m^2 = 161.29~m^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/4oo8hlxhanskt5a7jnyei2lasuk8rybwnh.png)
![x^2 = 122.85~m^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/qwfdh12zirpej4izxxqqi2iguizgmuiuq8.png)
![x = √(122.85~m^2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/f25ppgyhlebwpkdeav5u6z3wcjv8sdomzc.png)
![x = 11.1~m](https://img.qammunity.org/2020/formulas/mathematics/high-school/94ssui3dw0f7xp07xg3606t02mghfs9hwl.png)
2.
![\tan A = (opp)/(adj)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2bz2qywbkvmr2v2ss7ig4sg5rla9bh39b0.png)
![\tan 15^\circ = (18)/(x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/5j7fxdcdeqapubz6luqrx4qtvu5rmz3lj0.png)
![x\tan 15^\circ = 18](https://img.qammunity.org/2020/formulas/mathematics/high-school/z6aguauvyyrh5ml34p4c6nfpkxl6mbcmr5.png)
![x = (18)/(\tan 15^\circ)](https://img.qammunity.org/2020/formulas/mathematics/high-school/9pjyhjcdj7yx7tbl83ibhdgzwyrpuk3pjt.png)
![x = 67.2](https://img.qammunity.org/2020/formulas/mathematics/high-school/ex6c3bhl6166bhqtk139greap4opp0trhm.png)
3. The triangle has a 45-deg angle and a 90-deg angle.
45 + 90 + m<3 = 180
m<3 = 45
The third angle also measures 45 deg. This is a special case called 45-45-90 triangle. The sides opposite the congruent angles are congruent, so x = y. Now we can use the Pythagorean theorem.
![a^2 + b^2 = c^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7f61kw3dl3dz393m0wgdbl1ulni49sr4kp.png)
![x^2 + x^2 = (√(10))^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/9ebrusnqjx3qo8vn38kf1nk30tqa203vfq.png)
![2x^2 = 10](https://img.qammunity.org/2020/formulas/mathematics/high-school/s02rb8nr71219lk4we2ujnsn9u0sqb0vo4.png)
![x^2 = 5](https://img.qammunity.org/2020/formulas/mathematics/high-school/13iqe08jqedmy2s965p7w5f0742owr9ut1.png)
![x = √(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j5t7vvgdlwgj8ghplodq5bnjh8mbxe4py8.png)
![x = 2.24](https://img.qammunity.org/2020/formulas/mathematics/high-school/rxhy6xd5v95q1v3saojz9iiudo72wbpsyj.png)
![y = 2.24](https://img.qammunity.org/2020/formulas/mathematics/high-school/m2uhz6ysup2jsdtpxfqasuy3z8fm2yuohv.png)