Write a quadratic equation that has x-intercepts of -1/3 and 5/2

Question

asked Dec 24, 2020 15.9k views

1 Answer

Dummmy · Answer 1 · 2020-12-31T16:21:33+0000

Explanation:

Given that the two roots of the quadratic equation are
(-1)/(3) and
(5)/(2) .

If
$\alpha$
$,\beta$ are the roots of the quadratic equation,the equation is
$(x-\alpha )(x-\beta )$ .

It is given that
$\alpha =(-1)/(3)$ and
$\beta =(5)/(2)$ .

So,the equation is

(x-((-1)/(3)))(x-(5)/(2))

=
x^(2)-(5)/(2)x+(x)/(3)-(5)/(6)

=
6x^(2)-13x-5