Question

Write a quadratic equation that has x-intercepts of -1/3 and 5/2

Answer 1

Answer:
`6x^(2)-13x-5`

Explanation:

Given that the two roots of the quadratic equation are
`(-1)/(3)` and
`(5)/(2)`.

If
`\alpha`
`,\beta` are the roots of the quadratic equation,the equation is
`(x-\alpha )(x-\beta )`.

It is given that
`\alpha =(-1)/(3)` and
`\beta =(5)/(2)`.

So,the equation is

`(x-((-1)/(3)))(x-(5)/(2))`

=
`x^(2)-(5)/(2)x+(x)/(3)-(5)/(6)`

=
`6x^(2)-13x-5`