Question

2. A linearly-polarized em wave moving in vacuum perpendicular to a perfectly reflecting surface exerts a radiation pressure of 518 Pa on that surface. Find the intensity of that em eave.

Answer 1

The intensity of that em eave is
`1554*10^(8)\ W/m^2`

Step-by-step explanation:

Given that,

Pressure = 518 Pa

We need to calculate the intensity of that em eave

Using formula of pressure

`P=(I)/(c)`

`I=Pc`

Where,I = intensity of em eave

c = speed of light

P = pressure

Put the value into the formula

`I=518*3*10^(8)`

`I=1554*10^(8)\ W/m^2`

Hence, The intensity of that em eave is
`1554*10^(8)\ W/m^2`