Question

(50 points: will give you full points once somebody else answers/when i give you brain)

Anna is in charge of the alumni fundraiser for her alma mater. She is selling pre-sale tickets for $10 and at-the-door tickets for $25. The venue has the capacity to hold 400 people. The graph represents the number of tickets Anna needs to sell to offset her upfront costs and raise at least $5,000 for her school:


What is the minimum number of at-the-door tickets she needs to sell to make her goal?

333
334
66
67

i think it's 333

Answer 1

Answer:A 333

Step-by-step explanation:The reason behind my answer i have given is because they intersect at the 333 mark

Answer 2

67

Explanation:

Let us assume that Anna sells x number of pre-sale tickets and y number of at-the-door tickets.

Since, total capacity of the venue is 400, so we can write x + y = 400 ...... (1)

Now, given that each pre-sale ticket costs $10 and each at-the-door ticket costs $25, and total funds she needs to raise is $5000

So,we can write 10x + 25y = 5000, ⇒ x + 2.5y = 500 .... (2)

Now, solving equations (1) and (2) we get,

(2.5 - 1)y = 500 - 400 = 100

⇒ 1.5y = 100

⇒ y = 66.67

Hence, from equation (1) we get, x = 400 - 66.67 = 333.33

Since, y can not be a fraction and it can not be < 66.67 {Otherwise the goal of $5000 can not be achieved}

So, the minimum number of at-the-door ticket she needs to sell to make her goal is 67. (Answer)