Answer:
The perimeter of the given triangle is 19.24 cm.
Explanation:
Here, the given triangle is a right angled triangle.
Perpendicular AB = 5 cm
Hypotenuse AC = 8 cm
Let us assume the base AB = k units
Now, by PYTHAGORAS THEOREM in a right angled triangle:

Here, in ΔABC

⇒ AB = 6.24 cm
Now, the PERIMETER OF A TRIANGLE = AB + BC + AC
= 6.24 cm + 8 cm + 5 cm = 19.24 cm
Hence, the perimeter of the given triangle is 19.24 cm.