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Theater tickets for 8 people coast a total of $19.50. if a childs ticket cost $1.50 and an adults ticket cost $3.00, how many of these tickets were bought for adults

2 Answers

4 votes

Answer:

5 adults 3 children

Explanation:

WITH LOGIC:

The price for children is half of the price of adults

We could start thinking of 4 adults and 4 children

But total for 4 adults = $12 and total for 4 children( $6)

So the the total for 8 people is $18 (we still need to reach until $19.5)

We know that the number of children should be odd number (the total cost has decimals) so we know that 4 children is not an answer.

It should be 8 people in total

So since 4 adults ,4 children is not working

It is either 5 children and 3 adults or 5 adults and 3 children

So the answer is 5 adults and 3 children

5*3=15

3*1.5= 4.5

15+4.5=19.5

WITH EQUATION

a= adult c= child

a+c = 8 c=(8-a)

3a + 1.5(8-a) = 19.5

3a +12 - 1.5a = 19.5

1.5a=7.5

a=5

c=(8-5) c=3

User Xanarus
by
6.3k points
3 votes

Answer:

The number of tickets bought for adults is 4.

Explanation:

let us assume the number of tickets bought for children = x

And, the number of tickets bought for adults = y

Total number of tickets purchased = 8

Total Number of tickets = Number of ticket bought for {Adults + Children}

or, x + y = 8 .... (1)

Now, cost of 1 children ticket = $1.50

The cost of x children tickets = x ( Cost of 1 ticket) = x ($1.50) = 1.50 x

And, cost of 1 adult ticket = $3

The cost of y adult tickets = y ( Cost of 1 ticket) = y ($3) = 3y

So,total amount spent on the tickets =1.5 x + 3y

According to the question:

x + y = 8 .... (1)

1.5 x + 3y = 19.50 ..... (2)

To solve the given system, substitute the value of y = 8 - x from (1) in (2)

We get 1.5 x + 3y = 19.50 ⇒ 1.5 x + 3(8-x ) = 19.50

or, 1.5 x + 24 - 3x = 19.50

or, -1.5 x = 19.50 - 25.5

or, -1.5 x = 6 ⇒ x = 6/1.5 = 4

⇒ x = 4 ⇒ y = 8 - x = 8 - 4 = 4

or, x = 4, y = 4

Hence, the number of tickets bought for adults is y = 4.

User Mtelesha
by
6.1k points