Question

A very long, straight wire carries a current of 5.0 A. A particle, with a charge of -3 x 10-6 C and a speed of 100 m/s, is moving in a direction opposite of the current. The distance between moving charge in the wire is 0.1 m. What is the magnitude of the force on the moving charge?

Answer 1

The magnitude of the force on the moving charge is
`3*10^(-9)\ N`

Step-by-step explanation:

Given that,

Current = 5.0 A

Charge
`q=-3*10^(-6)\ C`

Speed v = 100 m/s

Distance = 0.1

We need to calculate the magnitude of the force on the moving charge

Using formula of force

`F=qvB`

`F=qv*(\mu_(0)I)/(2\pi r)`

Put the value into the formula

`F=-3*10^(-6)*100*(4\pi*10^(-7)*5.0)/(2\pi*0.1)`

`F=-3*10^(-9)\ N`

Hence, The magnitude of the force on the moving charge is
`3*10^(-9)\ N`