Question

Calculate the total resistance in a parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω. (Hint: When converting to a decimal from a fraction, keep the same number of significant figures in the decimal as was present in the original measurement from which the fraction was derived.)

Answer 1

Total resistance = 0.92Ω

Step-by-step explanation:

For parallel connected resistors we have effective resistance

`(1)/(R_(eff))=(1)/(R_1)+(1)/(R_2)+(1)/(R_3)+.....`

Here parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω.

That is

R₁ = 2Ω

R₂ = 3Ω

R₃ = 4Ω

Substituting

`(1)/(R_(eff))=(1)/(R_1)+(1)/(R_2)+(1)/(R_3)\\\\(1)/(R_(eff))=(1)/(2)+(1)/(3)+(1)/(4)\\\\(1)/(R_(eff))=(6+4+3)/(12)\\\\R_(eff)=(12)/(13)=0.92ohm`

Total resistance = 0.92Ω