Question

Emil's backpack weighs LaTeX: 6\frac{3}{8}6 3 8pounds. He removes a book that weighs LaTeX: \frac{3}{4}3 4 pound. Then he removes a book that weighs LaTeX: \frac{1}{2}1 2 pound. How much does Emil's backpack weigh now

Answer 1

Emil's backpack weighs
`7(5)/(8)` pounds

Explanation:

Given:

Weight of Emil's backpack=
`6(3)/(8)`

Weight of book 1 =
`(3)/(4)`

Weight of book 2 =
`(1)/(2)`

To Find:

The weight of Emil's backpack after books are removed=?

Solution:

weight of Emil's backpack after books are removed= Weight of backpack -Weight of book 1- Weight of book 2

Substituting the values,

weight of Emil's backpack after books are removed=
`6(3)/(8)-(3)/(4)-(1)/(2)`

=>
`(51)/(8)-(3)/(4)-(1)/(2)` (converting mixed fraction into normal fraction}

Taking LCM for the denominators

8= 2 x 2 x 2

4= 2 x 2

2= 2 x 1

Least Common Multiple(8,4,2) = 2 x 2 x 2

Least Common Multiple(8,4,2) = 8

so

=>
`(51)/(8)+(6)/(8)+(4)/(8)`

=>
`(51+6+4)/(8)`

=>
`(61)/(8)`

=>
`7(5)/(8)`