Question

Molarity of 82.6 g sucrose, C12H22O11, in 725 mL

Answer 1

0.33 M

Step-by-step explanation:

Given data:

Mass of sucrose = 82.6 g

Volume = 725 mL

Molarity = ?

Solution:

725/1000 = 0.725 L

Molarity = number of moles of solute / volume in litter

Number of moles of sucrose:

Number of moles = mass/molar mass

Number of moles = 82.6 g / 342.3 g/mol

Number of moles = 0.24 mol

Molarity = number of moles of solute / volume in litter

Molarity =0.24 mol / 0.725 L

Molarity = 0.33 M