Question

The average flow speed in a constant-diameter section of the Alaskan pipeline is 2.5 m/s. At the inlet, the pressure is 8.25 MPa (gage) and the elevation is 45 m; at the outlet, the pressure is 350 kPa (gage) and the elevation is 115 m. Calculate the head loss in this section of pipeline.

Answer 1

head loss = 805.327 m

Step-by-step explanation:

given data

average flow speed v = 2.5 m/s

inlet pressure Pi = 8.25 MPa

elevation Zi = 45 m

outlet pressure Po = 350 kPa

elevation Zo = 115 m

we consider oil Specific Gravity = 0.92

to find out

head loss in this section of pipeline

solution

we find here head loss that is inlet and outlet

Hi =
`(Pi)/(\rho g) +(Vi^2)/(2g) +Zi` ..............1

put here value

Hi =
`(8.25*10^6)/(920*9.81) +(2.5^2)/(2*9.81) +45`

Hi = 959.425 m

and

Hout =
`(Pout)/(\rho g) +(Vout^2)/(2g) +Zout` ..............2

put here value

H out =
`(350*10^3)/(920*9.81) +(2.5^2)/(2*9.81) +115`

H out = 154.098 m

so

head loss is = Hi - H out

head loss is = 959.425 - 154.098

head loss = 805.327 m