Question

What is the approximate energy of a photon having a frequency of 4 x 10^7 Hz (h=6.6 x 10^-34]•s)

Answer 1

E = 26.4 ×10⁻²⁷ j

Step-by-step explanation:

Given data:

Energy of energy =?

Frequency = 4×10⁷ Hz

Solution:

Formula:

E = hf

E = hf

E = 6.6 ×10⁻³⁴ m²Kg/s . 4×10⁷ Hz

Hz = s⁻¹

j = m²Kg/s ²

E = 26.4 ×10⁻²⁷ j.