Question

Un carro de juguete da vueltas en una pista circular de 45 cm de diametro si emplea 0,5 s en realizar una vuelta dteemina

Answer 1

Answers:

The complete question in english is written below:

A toy car spins on a circular track 45 cm in diameter. If it uses 0.5 seconds to make a complete circle, determine:

a- period and frequency in one circle

b-the distance it travels around the circular path

c-linear velocity

d-angular velocity

e-centripetal acceleration

a- period and frequency in one circle

According to the given information the period is
`T=0. 5s` and since the frequency
`f` is the inverse of the period, we have:

`f=(1)/(T)=(1)/(0.5 s)`

`f=2 Hz`

b-the distance it travels around the circular path

Here we have to calculate the perimeter
`P` of the circular path:

`P=\pi D`

Where
`D=45 cm=0.45 m` is the diameter

`P=\pi (0.45 m)=1.413 m`

c-linear velocity

We can calculate the linear velocity
`V` by:

`V=(P)/(T)=(1.413 m)/(0.5 s)`

`V=2.82 m/s`

d-angular velocity

Angular velocity
`\omega` is given by:

`\omega=2 \pi f`

`\omega=2 \pi (2 Hz)`

`\omega=12.56 rad/s`

e-centripetal acceleration

Centripetal acceleration
`a_(c)` is given by:

`a_(c)=(V^(2))/(r)`

`a_(c)=((2.82 m/s)^(2))/(0.225 m)`

`a_(c)=35.34 m/s^(2)`