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A Mars rover has a mass of 500 kg. The acceleration due to gravity in mars is about 3.7 m/s^2 and the coefficient of kinetic friction for the rover on the surface is 0.4. How much force must the rover’s engine exert in order to travel at a constant speed?

User Nioka
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1 Answer

5 votes

Answer:

740 N

Step-by-step explanation:

Friction equals normal force times coefficient of friction. On level ground, normal force equals weight.

Constant speed means no acceleration. Sum of the forces:

∑F = ma

F − mgμ = 0

F = mgμ

F = (500 kg) (3.7 m/s²) (0.4)

F = 740 N

User Enoch
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