Question

What is the equation of the graph below? A graph shows a parabola that opens up with a vertex at negative three comma negative one.

Answer 1

`y=(x+3)^2-1\\y=x^2+6x+8`

Explanation:

Given:

Vertex of the parabola is,
`(h,k)=(-3,-1)`

Equation of the parabola in vertex form is given as:

`y=(x-h)^2+k`

Plug in
`h=-3,k=-1`. This gives,

`y=(x-(-3))^2+(-1)\\y=(x+3)^2-1`

Therefore, the equation of the given graph is

`y=(x+3)^2-1\\y=x^2+6x+8`.