Question

How much kinetic energy will an electron gain (in joules) if it accelerates through a potential difference of 2.32×104 V ?How much kinetic energy will an electron gain (in joules) if it accelerates through a potential difference of 2.32×104 V ?

Answer 1

3.712 x 10^-15 J

Step-by-step explanation:

Potential difference, V = 2.32 x 10^4 V

Charge of electron, e = 1.6 x 10^-19 J

The kinetic energy of the electron is

K = e x V

K = 1.6 x 10^-19 x 2.32 x 10^4 J

K = 3.712 x 10^-15 J

Thus, the kinetic energy of the electron is 3.712 x 10^-15 J.

Answer 2

`\Delta KE=3.71* 10^(-15)\ J`

Step-by-step explanation:

It is given that,

Potential difference,
`PE=2.32* 10^4\ V`

Using the conservation of energy as the potential energy lost by an electron gets converted to the kinetic energy gained by it. Its relation is given by :

`\Delta KE=\Delta PE`

Since,
`\Delta PE=q\Delta V`

`\Delta KE=q\Delta V`

`\Delta KE=1.6* 10^(-19)* 2.32* 10^4\ V`

`\Delta KE=3.71* 10^(-15)\ J`

So, the kinetic energy gained by the electron is
`3.71* 10^(-15)\ J`