Answer: The mass of potassium superoxide required is 142.2 grams
Step-by-step explanation:
The chemical equation for the reaction of potassium superoxide with water follows:
![2KO_2+H_2O\rightarrow KOH+KHO_2+O_2;\Delta H=2405J](https://img.qammunity.org/2020/formulas/chemistry/college/c9i5wfi5aohvhn1ujdej3r82o0824huvne.png)
Number of moles of potassium superoxide reacted = 2 moles for given amount of heat released
To calculate the mass for given number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://img.qammunity.org/2020/formulas/chemistry/high-school/gwh5prgbdt4s2p8o8xquycz897bwt6lvw1.png)
Molar mass of potassium superoxide = 71.1 g/mol
Moles of potassium superoxide = 2 moles
Putting values in above equation, we get:
![2mol=\frac{\text{Mass of potassium superoxide}}{71.1g/mol}\\\\\text{Mass of potassium superoxide}=(2mol* 71.1g/mol)=142.2g](https://img.qammunity.org/2020/formulas/chemistry/college/ny31wocohuxjuu72laiehlsu740ozkf5qh.png)
Hence, the mass of potassium superoxide required is 142.2 grams