Answer:
option B
Step-by-step explanation:
The correct answer is option B
Initially, the weight of the wood pieces was counter-balanced by the upthrust provided by water which depended upon the volume of the first piece of wood that was inside the water (which was equal to the volume of water displaced).
Now when the second piece was placed in the water then again the weight of both the blocks individually (which doesn't change) would be counter-balanced by the upthrust of total volume (coming from contribution from both the blocks) which would be same as earlier.
Hence, the level of water would remain unchanged.